What is (2/(3*a^6*b^4*c^{-3)+11a*b^2})^2 ?

The solution to (2/(3*a^6*b^4*c^{-3)+11a*b^2})^2 is (4c^6)/((11ab^2c^3+3a^6b^4)^2)

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simplify (2/(3a^6b^4c^{-3)+11ab^2})^2

simplify

(\frac{2}{3 \cdot a ^{6} \cdot b ^{4} \cdot c ^{- 3} + 11 a \cdot b ^{2}})^{2}

\frac{4 c ^{6}}{( 11 a b ^{2} c ^{3} + 3 a ^{6} b ^{4} ) ^{2}}

Solution steps

(\frac{2}{3 a ^{6} b ^{4} c ^{- 3} + 11 a b ^{2}})^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{2 ^{2}}{( 3 a ^{6} b ^{4} c ^{- 3} + 11 a b ^{2} ) ^{2}}

2^{2} = 4

= \frac{4}{( 3 a ^{6} b ^{4} c ^{- 3} + 11 a b ^{2} ) ^{2}}

Simplify

(3 a^{6} b^{4} c^{- 3} + 11 a b^{2})^{2} : \frac{( 11 a b ^{2} c ^{3} + 3 a ^{6} b ^{4} ) ^{2}}{c ^{6}}

= \frac{4}{\frac{( 11 a b ^{2} c ^{3} + 3 a ^{6} b ^{4} ) ^{2}}{c ^{6}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{4 c ^{6}}{( 11 a b ^{2} c ^{3} + 3 a ^{6} b ^{4} ) ^{2}}

6 \cdot y^{- 2}

28 x^{4} y^{2} z - 16 x^{2} y^{3} z^{2} + 8 x^{3} y^{4} z^{3}

(2 x + 1 + 3)^{1}

(\frac{x ^{- 4}}{y ^{4}})^{- 5}

4 - 4 (3^{n}) + (3^{2})^{n}

What is (2/(3*a^6*b^4*c^{-3)+11a*b^2})^2 ?
The solution to (2/(3*a^6*b^4*c^{-3)+11a*b^2})^2 is (4c^6)/((11ab^2c^3+3a^6b^4)^2)