What is w^{-2}3+w^{-2}8 ?

The solution to w^{-2}3+w^{-2}8 is (11)/(w^2)

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simplify w^{-2}3+w^{-2}8

simplify

w^{- 2} 3 + w^{- 2} 8

\frac{11}{w ^{2}}

Solution steps

w^{- 2} \cdot 3 + w^{- 2} \cdot 8

Add similar elements:

w^{- 2} \cdot 3 + w^{- 2} \cdot 8 = 11 w^{- 2}

= 11 w^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

w^{- 2} = \frac{1}{w ^{2}}

= 11 \cdot \frac{1}{w ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{11 \cdot 1}{w ^{2}}

Multiply the numbers:

11 \cdot 1 = 11

= \frac{11}{w ^{2}}

30 x + 90 y

10 c^{1} + 10 c^{3} + 10 c^{5} + 10 c^{7}

\frac{1}{x} + \frac{x}{x} + 1

a^{3} - 9 b^{3} + (a + b)^{3}

\frac{27 a}{3}