What is ((5x^2-33x-14))/((x^2-7x)) ?

The solution to ((5x^2-33x-14))/((x^2-7x)) is (5x+2)/x

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simplify ((5x^2-33x-14))/((x^2-7x))

simplify

\frac{( 5 x ^{2} - 33 x - 14 )}{( x ^{2} - 7 x )}

\frac{5 x + 2}{x}

Solution steps

\frac{5 x ^{2} - 33 x - 14}{x ^{2} - 7 x}

Factor

5 x^{2} - 33 x - 14 : (5 x + 2) (x - 7)

= \frac{( 5 x + 2 ) ( x - 7 )}{x ^{2} - 7 x}

Factor

x^{2} - 7 x : x (x - 7)

= \frac{( 5 x + 2 ) ( x - 7 )}{x ( x - 7 )}

Cancel the common factor:

x - 7

= \frac{5 x + 2}{x}

(y^{5})^{4}

(a - 6)^{3}

8 (a + 1)^{3} - 1

(- x + 2) (3 - x)

(\frac{2 x + 1}{2})^{3}

What is ((5x^2-33x-14))/((x^2-7x)) ?
The solution to ((5x^2-33x-14))/((x^2-7x)) is (5x+2)/x