What is factor y^3+y^2-4y-64 ?

The solution to factor y^3+y^2-4y-64 is (y-4)(y^2+5y+16)

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factor y^3+y^2-4y-64

factor

y^{3} + y^{2} - 4 y - 64

(y - 4) (y^{2} + 5 y + 16)

Solution steps

y^{3} + y^{2} - 4 y - 64

Use the rational root theorem

= (y - 4) \frac{y ^{3} + y ^{2} - 4 y - 64}{y - 4}

\frac{y ^{3} + y ^{2} - 4 y - 64}{y - 4} = y^{2} + 5 y + 16

= (y - 4) (y^{2} + 5 y + 16)

a^{0.2} - 16 + 26 - 2 \cdot 3 + 3 (2 \cdot 4)

(1 + a + b)^{3}

\frac{( - 4 x ^{3} y ^{4} ) ^{- 2}}{( 6 x ^{2} y ^{5} ) ^{- 2}}

\frac{( w ^{2} + 2 w )}{w}

(3 y + 7)^{2}

What is factor y^3+y^2-4y-64 ?
The solution to factor y^3+y^2-4y-64 is (y-4)(y^2+5y+16)