What are the solutions to the equation 3x^2-4x+16=0 ?

The solutions to the equation 3x^2-4x+16=0 are x= 2/3+i(2sqrt(11))/3 ,x= 2/3-i(2sqrt(11))/3

Find the zeros of 3x^2-4x+16=0

The zeros of 3x^2-4x+16=0 are x= 2/3+i(2sqrt(11))/3 ,x= 2/3-i(2sqrt(11))/3

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3 x^{2} - 4 x + 16 = 0

x = \frac{2}{3} + i \frac{2 11}{3}, x = \frac{2}{3} - i \frac{2 11}{3}

Solution steps

3 x^{2} - 4 x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 16}{2 \cdot 3}

Simplify

(- 4)^{2} - 4 \cdot 3 \cdot 16 : 411 i

x_{1, 2} = \frac{- ( - 4 ) \pm 4 11 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 4 11 i}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 4 11 i}{2 \cdot 3}

x = \frac{- ( - 4 ) + 4 11 i}{2 \cdot 3} : \frac{2}{3} + i \frac{2 11}{3}

x = \frac{- ( - 4 ) - 4 11 i}{2 \cdot 3} : \frac{2}{3} - i \frac{2 11}{3}

The solutions to the quadratic equation are:

x = \frac{2}{3} + i \frac{2 11}{3}, x = \frac{2}{3} - i \frac{2 11}{3}

2 C - (- 5 C) = - (- 3 C)

- 2 (4 - x) = 6 (x + 2) + 3 x

4 x^{2} - 21 x - 18 = 0

(h - 6) (8 h - 1) = 0

∣ x - 1 ∣ = 0

What are the solutions to the equation 3x^2-4x+16=0 ?
The solutions to the equation 3x^2-4x+16=0 are x= 2/3+i(2sqrt(11))/3 ,x= 2/3-i(2sqrt(11))/3
Find the zeros of 3x^2-4x+16=0
The zeros of 3x^2-4x+16=0 are x= 2/3+i(2sqrt(11))/3 ,x= 2/3-i(2sqrt(11))/3