What is factor 16a^4-4a^2-4a-1 ?

The solution to factor 16a^4-4a^2-4a-1 is (4a^2+2a+1)(4a^2-2a-1)

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factor 16a^4-4a^2-4a-1

factor

16 a^{4} - 4 a^{2} - 4 a - 1

(4 a^{2} + 2 a + 1) (4 a^{2} - 2 a - 1)

Solution steps

16 a^{4} - 4 a^{2} - 4 a - 1

Factor

- 4 a^{2} - 4 a - 1 : - (2 a + 1)^{2}

= 16 a^{4} - (2 a + 1)^{2}

Simplify

16 a^{4} : (4 a^{2})^{2}

= (4 a^{2})^{2} - (2 a + 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(4 a^{2})^{2} - (2 a + 1)^{2} = (4 a^{2} + (2 a + 1)) (4 a^{2} - (2 a + 1))

= (4 a^{2} + (2 a + 1)) (4 a^{2} - (2 a + 1))

Simplify

(4 a^{2} + (2 a + 1)) (4 a^{2} - (2 a + 1)) : (4 a^{2} + 2 a + 1) (4 a^{2} - 2 a - 1)

= (4 a^{2} + 2 a + 1) (4 a^{2} - 2 a - 1)

2 x^{3} + 54 y^{3}

\frac{1}{cos ( c )}

x^{3} y + 729 y^{4}

(4 a + 5 b)^{3}

2 \frac{x}{( x + 1 )} + 5 \frac{x}{( x + 1 )}

What is factor 16a^4-4a^2-4a-1 ?
The solution to factor 16a^4-4a^2-4a-1 is (4a^2+2a+1)(4a^2-2a-1)