What is factor 4x^2-9y^2+20x+25 ?

The solution to factor 4x^2-9y^2+20x+25 is (2x+5+3y)(2x+5-3y)

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factor 4x^2-9y^2+20x+25

factor

4 x^{2} - 9 y^{2} + 20 x + 25

(2 x + 5 + 3 y) (2 x + 5 - 3 y)

Solution steps

4 x^{2} - 9 y^{2} + 20 x + 25

Factor

4 x^{2} + 20 x + 25 : (2 x + 5)^{2}

= (2 x + 5)^{2} - 9 y^{2}

Simplify

9 y^{2} : (3 y)^{2}

= (2 x + 5)^{2} - (3 y)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 x + 5)^{2} - (3 y)^{2} = ((2 x + 5) + 3 y) ((2 x + 5) - 3 y)

= ((2 x + 5) + 3 y) ((2 x + 5) - 3 y)

Apply rule:

(a) = a

(2 x + 5) = 2 x + 5

= (2 x + 5 + 3 y) (2 x + 5 - 3 y)

\frac{3}{( x ^{2} - 4 )} + \frac{1}{( x - 2 ) ^{2}}

a^{10} + x^{10}

(i) x^{3} - 2 x^{2} - x + 2

12 x y^{2} - 24 x^{3} y^{3}

4 x [x [5 x - (6 - x)] - (x - 1) (5 x + 1)] + 4

What is factor 4x^2-9y^2+20x+25 ?
The solution to factor 4x^2-9y^2+20x+25 is (2x+5+3y)(2x+5-3y)