What is (2/3 m-1/2 m+1)+(-1/2 m^2+2/3 m-1) ?

The solution to (2/3 m-1/2 m+1)+(-1/2 m^2+2/3 m-1) is 5/6 m-1/2 m^2

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simplify (2/3 m-1/2 m+1)+(-1/2 m^2+2/3 m-1)

simplify

(\frac{2}{3} m - \frac{1}{2} m + 1) + (- \frac{1}{2} m^{2} + \frac{2}{3} m - 1)

\frac{5}{6} m - \frac{1}{2} m^{2}

Solution steps

(\frac{2}{3} m - \frac{1}{2} m + 1) + (- \frac{1}{2} m^{2} + \frac{2}{3} m - 1)

Simplify

(\frac{2}{3} m - \frac{1}{2} m + 1) + (- \frac{1}{2} m^{2} + \frac{2}{3} m - 1) : \frac{2}{3} m - \frac{1}{2} m + 1 - \frac{1}{2} m^{2} + \frac{2}{3} m - 1

= \frac{2}{3} m - \frac{1}{2} m + 1 - \frac{1}{2} m^{2} + \frac{2}{3} m - 1

Group like terms

= \frac{2}{3} m + \frac{2}{3} m - \frac{1}{2} m - \frac{1}{2} m^{2} + 1 - 1

Add similar elements:

\frac{2}{3} m + \frac{2}{3} m = 2 \cdot \frac{2}{3} m

= 2 \cdot \frac{2}{3} m - \frac{1}{2} m - \frac{1}{2} m^{2} + 1 - 1

Factor out common term

m

= m (2 \cdot \frac{2}{3} - \frac{1}{2}) - \frac{1}{2} m^{2} + 1 - 1

Subtract the numbers:

1 - 1 = 0

= m (2 \cdot \frac{2}{3} - \frac{1}{2}) - \frac{1}{2} m^{2}

2 \cdot \frac{2}{3} - \frac{1}{2} = \frac{5}{6}

= m \frac{5}{6} - \frac{1}{2} m^{2}

= \frac{5}{6} m - \frac{1}{2} m^{2}

(d + 2)^{3}

(\frac{2 x + 3}{x - 1})^{2}

64 (a + 2 b)^{3} - 343 (a - 2 b)^{3}

x^{4} + 5 x^{2} + 9

\frac{\frac{( 2 x )}{5}}{\frac{12}{15}}

What is (2/3 m-1/2 m+1)+(-1/2 m^2+2/3 m-1) ?
The solution to (2/3 m-1/2 m+1)+(-1/2 m^2+2/3 m-1) is 5/6 m-1/2 m^2