What is ((x^2+1}{x^2})-4(\frac{x+1)/x)+6 ?

The solution to ((x^2+1}{x^2})-4(\frac{x+1)/x)+6 is (x^2+1}{x^2}-\frac{4(x+1))/x+6

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simplify ((x^2+1}{x^2})-4(\frac{x+1)/x)+6

simplify

(\frac{x ^{2} + 1}{x ^{2}}) - 4 (\frac{x + 1}{x}) + 6

\frac{x ^{2} + 1}{x ^{2}} - \frac{4 ( x + 1 )}{x} + 6

Solution steps

(\frac{x ^{2} + 1}{x ^{2}}) - 4 (\frac{x + 1}{x}) + 6

Apply rule:

(a) = a

(\frac{x ^{2} + 1}{x ^{2}}) = \frac{x ^{2} + 1}{x ^{2}}

= \frac{x ^{2} + 1}{x ^{2}} - 4 \cdot \frac{x + 1}{x} + 6

Simplify

4 \cdot \frac{x + 1}{x} : \frac{4 ( x + 1 )}{x}

= \frac{x ^{2} + 1}{x ^{2}} - \frac{4 ( x + 1 )}{x} + 6

\frac{x ^{2}}{y ^{2}} - 2 - 3 \frac{y ^{2}}{x ^{2}}

(x - y)^{3} + (y - 2)^{3} + (2 - x)^{3}

(a + b)^{19}

(2 x + 3 y)^{3} - (2 x - 3 y)^{3}

(5 x^{2} + 7 y^{3})^{3}

What is ((x^2+1}{x^2})-4(\frac{x+1)/x)+6 ?
The solution to ((x^2+1}{x^2})-4(\frac{x+1)/x)+6 is (x^2+1}{x^2}-\frac{4(x+1))/x+6