What is (3+2i)(2-i)-(1-i)(2-3i) ?

The solution to (3+2i)(2-i)-(1-i)(2-3i) is 9+6i

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simplify (3+2i)(2-i)-(1-i)(2-3i)

simplify

(3 + 2 i) (2 - i) - (1 - i) (2 - 3 i)

9 + 6 i

Solution steps

(3 + 2 i) (2 - i) - (1 - i) (2 - 3 i)

(3 + 2 i) (2 - i) = 8 + i

(1 - i) (2 - 3 i) = - 1 - 5 i

= 8 + i - (- 1 - 5 i)

Expand

- (- 1 - 5 i) : 1 + 5 i

= 8 + i + 1 + 5 i

Group like terms

= i + 5 i + 8 + 1

Add similar elements:

i + 5 i = 6 i

= 6 i + 8 + 1

Add the numbers:

8 + 1 = 9

= 6 i + 9

Rewrite in standard complex form:

9 + 6 i

= 9 + 6 i

6 (2 x - 2) = 19 (x - 12)

5 x - 1 = 4 x

8 y - 3 = 17 - 2 y

x^{2} + 8 x + 7

x^{5} - 5 x^{3} - 36 x

What is (3+2i)(2-i)-(1-i)(2-3i) ?
The solution to (3+2i)(2-i)-(1-i)(2-3i) is 9+6i