What is (((x-3)(x+1)+7))/((x-4)) ?

The solution to (((x-3)(x+1)+7))/((x-4)) is (x^2-2x+4)/(x-4)

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simplify (((x-3)(x+1)+7))/((x-4))

simplify

\frac{( ( x - 3 ) ( x + 1 ) + 7 )}{( x - 4 )}

\frac{x ^{2} - 2 x + 4}{x - 4}

Solution steps

\frac{( x - 3 ) ( x + 1 ) + 7}{x - 4}

Expand

(x - 3) (x + 1) : x^{2} - 2 x - 3

= \frac{x ^{2} - 2 x - 3 + 7}{x - 4}

Add the numbers:

- 3 + 7 = 4

= \frac{x ^{2} - 2 x + 4}{x - 4}

a^{12} - b^{12}

(11 a^{16} b^{3}) (\frac{4 a ^{3} b ^{6}}{c ^{8}})^{- 5}

x^{2} - 4 x + 4 y - y^{2}

\frac{\frac{1}{2}}{\frac{x}{a}} a^{2} + 2 a^{3} - 4 a^{4}

(\frac{3}{2 \cdot x + 1})^{3}

What is (((x-3)(x+1)+7))/((x-4)) ?
The solution to (((x-3)(x+1)+7))/((x-4)) is (x^2-2x+4)/(x-4)