en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor p^8+p^4+1

Solution

factor

p^{8} + p^{4} + 1

Solution

(p^{2} + p + 1) (p^{2} - p + 1) (p^{4} - p^{2} + 1)

Solution steps

p^{8} + p^{4} + 1

Add and subtract

p^{4}

= p^{8} + 2 p^{4} + 1 - p^{4}

Factor

p^{8} + 2 p^{4} + 1 : (p^{4} + 1)^{2}

= (p^{4} + 1)^{2} - p^{4}

Factor

(p^{4} + 1)^{2} - p^{4} : (p^{4} + 1 + p^{2}) (p^{4} + 1 - p^{2})

= (p^{4} + 1 + p^{2}) (p^{4} + 1 - p^{2})

Factor

p^{4} + 1 + p^{2} : (p^{2} + 1 + p) (p^{2} + 1 - p)

= (p^{2} + 1 + p) (p^{2} + 1 - p) (p^{4} + 1 - p^{2})

= (p^{2} + p + 1) (p^{2} - p + 1) (p^{4} - p^{2} + 1)

Popular Examples

simplify (2x^2+6y)3 simplify

(2 x^{2} + 6 y) 3

simplify ((6w^2*x^6*w^6))/((2w*x^3))simplify

\frac{( 6 w ^{2} \cdot x ^{6} \cdot w ^{6} )}{( 2 w \cdot x ^{3} )}

simplify (a-b)^3-(a+b)^3 simplify

(a - b)^{3} - (a + b)^{3}

factor 8x-4y+12z factor

8 x - 4 y + 12 z

expand (4x+5y)^3 expand

(4 x + 5 y)^{3}

Frequently Asked Questions (FAQ)

What is factor p^8+p^4+1 ?
The solution to factor p^8+p^4+1 is (p^2+p+1)(p^2-p+1)(p^4-p^2+1)