What is ((x^2-2x+1))/((x^2-1)) ?

The solution to ((x^2-2x+1))/((x^2-1)) is (x-1)/(x+1)

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simplify ((x^2-2x+1))/((x^2-1))

simplify

\frac{( x ^{2} - 2 x + 1 )}{( x ^{2} - 1 )}

\frac{x - 1}{x + 1}

Solution steps

\frac{x ^{2} - 2 x + 1}{x ^{2} - 1}

Factor

x^{2} - 2 x + 1 : (x - 1)^{2}

= \frac{( x - 1 ) ^{2}}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x - 1 ) ^{2}}{( x + 1 ) ( x - 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x - 1)^{2} = (x - 1) (x - 1)

= \frac{( x - 1 ) ( x - 1 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x - 1}{x + 1}

m^{2} (n^{2} + 4 n - 5) - m^{4} (n^{2} + 4 n - 5)

a^{3} - a^{2} \cdot b + a \cdot b^{2} - b^{3}

\frac{( a - a )}{( a - 1 )}

(a + b)^{4} + (a - b)^{4}

15 x^{2} (5 x^{3} - 6)^{5}

What is ((x^2-2x+1))/((x^2-1)) ?
The solution to ((x^2-2x+1))/((x^2-1)) is (x-1)/(x+1)