What are the solutions to the equation 2x^2+15x=8 ?

The solutions to the equation 2x^2+15x=8 are x= 1/2 ,x=-8

Find the zeros of 2x^2+15x=8

The zeros of 2x^2+15x=8 are x= 1/2 ,x=-8

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2 x^{2} + 15 x = 8

x = \frac{1}{2}, x = - 8

Decimal Notation

x = 0.5, x = - 8

Solution steps

2 x^{2} + 15 x = 8

Move

8

to the left side

2 x^{2} + 15 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

1 5^{2} - 4 \cdot 2 (- 8) = 17

x_{1, 2} = \frac{- 15 \pm 17}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 15 + 17}{2 \cdot 2}, x_{2} = \frac{- 15 - 17}{2 \cdot 2}

x = \frac{- 15 + 17}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 15 - 17}{2 \cdot 2} : - 8

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 8

3 x^{3} - 33 x^{2} + 90 x

x^{2} - 20 x + 13 = 0

3 x + 2 = 4

2 x + 1 = - 2 x + 5

9^{\frac{1}{4}} \cdot 9^{\frac{1}{4}}

What are the solutions to the equation 2x^2+15x=8 ?
The solutions to the equation 2x^2+15x=8 are x= 1/2 ,x=-8
Find the zeros of 2x^2+15x=8
The zeros of 2x^2+15x=8 are x= 1/2 ,x=-8