What is (4i^w*k^{-3-n})(-j*k^{n+3}) ?

The solution to (4i^w*k^{-3-n})(-j*k^{n+3}) is -4i^wj

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simplify (4i^wk^{-3-n})(-jk^{n+3})

simplify

(4 i^{w} \cdot k^{- 3 - n}) (- j \cdot k^{n + 3})

- 4 i^{w} j

Solution steps

(4 i^{w} k^{- 3 - n}) (- j k^{n + 3})

Apply rule:

a (- b) = - ab

(4 i^{w} k^{- 3 - n}) (- j k^{n + 3}) = - 4 i^{w} k^{- 3 - n} j k^{n + 3}

= - 4 i^{w} k^{- 3 - n} j k^{n + 3}

Simplify

k^{- 3 - n} k^{n + 3} : k^{0}

= - 4 i^{w} k^{0} j

Simplify

- 4 i^{w} k^{0} j : - 4 j i^{w}

= - 4 j i^{w}

= - 4 i^{w} j

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\frac{121}{144} \cdot x^{8} \cdot y^{6} - \frac{4}{25} \cdot z^{14}

\frac{( x ^{2} + 2 x - 3 )}{( x - 1 )}

\frac{( y ^{2} )}{( x ^{2} + y ^{2} + x )}

What is (4i^w*k^{-3-n})(-j*k^{n+3}) ?
The solution to (4i^w*k^{-3-n})(-j*k^{n+3}) is -4i^wj