What is (((256a^{16})}{(81b^4)})^{\frac{-3)/4} ?

The solution to (((256a^{16})}{(81b^4)})^{\frac{-3)/4} is (27b^3)/(64a^{12)}

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simplify (((256a^{16})}{(81b^4)})^{\frac{-3)/4}

simplify

(\frac{( 256 a ^{16} )}{( 81 b ^{4} )})^{\frac{- 3}{4}}

\frac{27 b ^{3}}{64 a ^{12}}

Solution steps

(\frac{256 a ^{16}}{81 b ^{4}})^{\frac{- 3}{4}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 256 a ^{16} ) ^{\frac{- 3}{4}}}{( 81 b ^{4} ) ^{\frac{- 3}{4}}}

Simplify

(256 a^{16})^{\frac{- 3}{4}} : \frac{1}{64 a ^{12}}

= \frac{\frac{1}{64 a ^{12}}}{( 81 b ^{4} ) ^{\frac{- 3}{4}}}

Simplify

(81 b^{4})^{\frac{- 3}{4}} : \frac{1}{27 b ^{3}}

= \frac{\frac{1}{64 a ^{12}}}{\frac{1}{27 b ^{3}}}

Simplify

\frac{\frac{1}{64 a ^{12}}}{\frac{1}{27 b ^{3}}} : \frac{27 b ^{3}}{64 a ^{12}}

= \frac{27 b ^{3}}{64 a ^{12}}

a^{4} + a^{2} \cdot b^{2} + b^{4}

x^{4} - 3 x - 2

15 x^{3} + 3 x^{2} y

(r + 2)^{3}

x^{3} - 1 - 2 x^{2} + 2 x

What is (((256a^{16})}{(81b^4)})^{\frac{-3)/4} ?
The solution to (((256a^{16})}{(81b^4)})^{\frac{-3)/4} is (27b^3)/(64a^{12)}