What is (x+y+z)^2+(x+y/2+2/3)^2 ?

The solution to (x+y+z)^2+(x+y/2+2/3)^2 is x^2+2xy+2xz+y^2+2yz+z^2+((6x+3y+4)^2)/(36)

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simplify (x+y+z)^2+(x+y/2+2/3)^2

simplify

(x + y + z)^{2} + (x + \frac{y}{2} + \frac{2}{3})^{2}

x^{2} + 2 x y + 2 x z + y^{2} + 2 yz + z^{2} + \frac{( 6 x + 3 y + 4 ) ^{2}}{36}

Solution steps

(x + y + z)^{2} + (x + \frac{y}{2} + \frac{2}{3})^{2}

Simplify

(x + \frac{y}{2} + \frac{2}{3})^{2} : \frac{( 6 x + 3 y + 4 ) ^{2}}{36}

= (x + y + z)^{2} + \frac{( 6 x + 3 y + 4 ) ^{2}}{36}

Expand

(x + y + z)^{2} : x^{2} + 2 x y + 2 x z + y^{2} + 2 yz + z^{2}

= x^{2} + 2 x y + 2 x z + y^{2} + 2 yz + z^{2} + \frac{( 6 x + 3 y + 4 ) ^{2}}{36}

(v) (\frac{3}{( 2 2 )})^{2}

x^{2} y - x^{3} - 9 y + 9 x

(2 a^{4} + 6 b^{3})^{6}

\frac{( - 2 x ^{2} ) ( x ^{2} - 2 x + 3 ) 1}{2}

\frac{( - 10 y ^{5} )}{( - 2 y )}

What is (x+y+z)^2+(x+y/2+2/3)^2 ?
The solution to (x+y+z)^2+(x+y/2+2/3)^2 is x^2+2xy+2xz+y^2+2yz+z^2+((6x+3y+4)^2)/(36)