What is factor 16m^4-25m^2*n^2+9n^4 ?

The solution to factor 16m^4-25m^2*n^2+9n^4 is (4m+3n)(4m-3n)(m+n)(m-n)

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factor 16m^4-25m^2*n^2+9n^4

factor

16 m^{4} - 25 m^{2} \cdot n^{2} + 9 n^{4}

(4 m + 3 n) (4 m - 3 n) (m + n) (m - n)

Solution steps

16 m^{4} - 25 m^{2} n^{2} + 9 n^{4}

Break the expression into groups

= (16 m^{4} - 9 m^{2} n^{2}) + (- 16 m^{2} n^{2} + 9 n^{4})

Factor out

m^{2}

from

16 m^{4} - 9 m^{2} n^{2} : m^{2} (16 m^{2} - 9 n^{2})

Factor out

- n^{2}

from

- 16 m^{2} n^{2} + 9 n^{4} : - n^{2} (16 m^{2} - 9 n^{2})

= m^{2} (16 m^{2} - 9 n^{2}) - n^{2} (16 m^{2} - 9 n^{2})

Factor out common term

16 m^{2} - 9 n^{2}

= (16 m^{2} - 9 n^{2}) (m^{2} - n^{2})

Factor

16 m^{2} - 9 n^{2} : (4 m + 3 n) (4 m - 3 n)

= (4 m + 3 n) (4 m - 3 n) (m^{2} - n^{2})

Factor

m^{2} - n^{2} : (m + n) (m - n)

= (4 m + 3 n) (4 m - 3 n) (m + n) (m - n)

8 x^{3} + 3^{3}

i^{2} + o^{3}

3^{n} \cdot 9^{n + 1}

sin (9 0^{\circ}) + a

m^{3} - 2 m^{2} - 2 m - 3

What is factor 16m^4-25m^2*n^2+9n^4 ?
The solution to factor 16m^4-25m^2*n^2+9n^4 is (4m+3n)(4m-3n)(m+n)(m-n)