What is factor 64a^3+b^3 ?

The solution to factor 64a^3+b^3 is (4a+b)(16a^2-4ab+b^2)

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factor 64a^3+b^3

factor

64 a^{3} + b^{3}

(4 a + b) (16 a^{2} - 4 ab + b^{2})

Solution steps

64 a^{3} + b^{3}

Apply exponent rules

= (4 a)^{3} + b^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(4 a)^{3} + b^{3} = (4 a + b) ((4 a)^{2} - 4 ab + b^{2})

= (4 a + b) ((4 a)^{2} - 4 ab + b^{2})

Simplify

(4 a)^{2} - 4 ab + b^{2} : 16 a^{2} - 4 ab + b^{2}

= (4 a + b) (16 a^{2} - 4 ab + b^{2})

(a - b)^{10}

3 \frac{m ^{2}}{n ^{2}} - 11 + 10 \frac{n ^{2}}{m ^{2}}

2 x^{3} y - 4 x y

(\frac{x}{3 - 1})^{3}

\frac{2 x ^{7} + 8}{2}

What is factor 64a^3+b^3 ?
The solution to factor 64a^3+b^3 is (4a+b)(16a^2-4ab+b^2)