What is [((x^{10}))/((32y^{25))}]^{1/5} ?

The solution to [((x^{10}))/((32y^{25))}]^{1/5} is (x^2)/(2y^5)

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simplify [((x^{10}))/((32y^{25))}]^{1/5}

simplify

[\frac{( x ^{10} )}{( 32 y ^{25} )}]^{\frac{1}{5}}

\frac{x ^{2}}{2 y ^{5}}

Solution steps

(\frac{x ^{10}}{32 y ^{25}})^{\frac{1}{5}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( x ^{10} ) ^{\frac{1}{5}}}{( 32 y ^{25} ) ^{\frac{1}{5}}}

Simplify

(x^{10})^{\frac{1}{5}} : x^{2}

= \frac{x ^{2}}{( 32 y ^{25} ) ^{\frac{1}{5}}}

Simplify

(32 y^{25})^{\frac{1}{5}} : 2 y^{5}

= \frac{x ^{2}}{2 y ^{5}}

((x^{2} - 1)) \frac{3}{100} x^{2}

\frac{( p ^{2} )}{( ( p - y ) ^{y} )} - \frac{( 2 p )}{( ( p - y ) ^{y - 1} )} + \frac{1}{( ( p - y ) ^{y - 2} )}

x^{3} + 4 x + 5

(5 x \cdot y^{2})^{3}

(2 x - 1)^{3} + (2 - 2 x)^{3}

What is [((x^{10}))/((32y^{25))}]^{1/5} ?
The solution to [((x^{10}))/((32y^{25))}]^{1/5} is (x^2)/(2y^5)