What is factor 16x^4+8x^3-2x-1 ?

The solution to factor 16x^4+8x^3-2x-1 is (2x+1)(2x-1)(4x^2+2x+1)

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factor 16x^4+8x^3-2x-1

factor

16 x^{4} + 8 x^{3} - 2 x - 1

(2 x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

Solution steps

16 x^{4} + 8 x^{3} - 2 x - 1

= (16 x^{4} + 8 x^{3}) + (- 2 x - 1)

Factor out

8 x^{3}

from

16 x^{4} + 8 x^{3} : 8 x^{3} (2 x + 1)

Factor out

- 1

from

- 2 x - 1 : - (2 x + 1)

= 8 x^{3} (2 x + 1) - (2 x + 1)

Factor out common term

(2 x + 1) : (2 x + 1) (8 x^{3} - 1)

= (2 x + 1) (8 x^{3} - 1)

Factor

8 x^{3} - 1 : (2 x - 1) (2^{2} x^{2} + 2 x + 1)

= (2 x + 1) (2 x - 1) (2^{2} x^{2} + 2 x + 1)

2^{2} = 4

= (2 x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

14 x^{6} - 45 x^{3} y^{3} - 14 y^{6}

(3 y + 2 x)^{10}

(2 a + b - c)^{3}

\frac{10 ( r ^{35} p ^{9} )}{( - q )}

(1 - x) (1 + x) (1 + x^{2}) (1 + x^{4})

What is factor 16x^4+8x^3-2x-1 ?
The solution to factor 16x^4+8x^3-2x-1 is (2x+1)(2x-1)(4x^2+2x+1)