What are the solutions to the equation 4x^2-36x+77=0 ?

The solutions to the equation 4x^2-36x+77=0 are x= 11/2 ,x= 7/2

Find the zeros of 4x^2-36x+77=0

The zeros of 4x^2-36x+77=0 are x= 11/2 ,x= 7/2

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4 x^{2} - 36 x + 77 = 0

x = \frac{11}{2}, x = \frac{7}{2}

Decimal Notation

x = 5.5, x = 3.5

Solution steps

4 x^{2} - 36 x + 77 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 4 \cdot 77}{2 \cdot 4}

(- 36)^{2} - 4 \cdot 4 \cdot 77 = 8

x_{1, 2} = \frac{- ( - 36 ) \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 8}{2 \cdot 4}, x_{2} = \frac{- ( - 36 ) - 8}{2 \cdot 4}

x = \frac{- ( - 36 ) + 8}{2 \cdot 4} : \frac{11}{2}

x = \frac{- ( - 36 ) - 8}{2 \cdot 4} : \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{11}{2}, x = \frac{7}{2}

57 + 36 g \leq - 5

3^{2} + 6^{2}

3 = \frac{4 x + 27}{5}

0.09

15 - 4 x = 10 x + 45

What are the solutions to the equation 4x^2-36x+77=0 ?
The solutions to the equation 4x^2-36x+77=0 are x= 11/2 ,x= 7/2
Find the zeros of 4x^2-36x+77=0
The zeros of 4x^2-36x+77=0 are x= 11/2 ,x= 7/2