What is (x-1)(x-2)-(x-3)(x-4)+(x+5)(x+6) ?

The solution to (x-1)(x-2)-(x-3)(x-4)+(x+5)(x+6) is x^2+15x+20

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x-1)(x-2)-(x-3)(x-4)+(x+5)(x+6)

simplify

(x - 1) (x - 2) - (x - 3) (x - 4) + (x + 5) (x + 6)

x^{2} + 15 x + 20

Solution steps

(x - 1) (x - 2) - (x - 3) (x - 4) + (x + 5) (x + 6)

Expand

(x - 1) (x - 2) : x^{2} - 3 x + 2

= x^{2} - 3 x + 2 - (x - 3) (x - 4) + (x + 5) (x + 6)

Expand

- (x - 3) (x - 4) : - x^{2} + 7 x - 12

= x^{2} - 3 x + 2 - x^{2} + 7 x - 12 + (x + 5) (x + 6)

Expand

(x + 5) (x + 6) : x^{2} + 11 x + 30

= x^{2} - 3 x + 2 - x^{2} + 7 x - 12 + x^{2} + 11 x + 30

Group like terms

= x^{2} - x^{2} + x^{2} - 3 x + 7 x + 11 x + 2 - 12 + 30

Add similar elements:

x^{2} - x^{2} + x^{2} = x^{2}

= x^{2} - 3 x + 7 x + 11 x + 2 - 12 + 30

Add similar elements:

- 3 x + 7 x + 11 x = 15 x

= x^{2} + 15 x + 2 - 12 + 30

Add the numbers:

2 - 12 + 30 = 20

= x^{2} + 15 x + 20

(2 a^{5} + 4 b^{3}) 3

(\frac{x}{3 + 1})^{2}

(\frac{x + 1}{x - 1})^{2}

3 x - (3 x - 2)

(- 3 a^{2} \cdot b)^{2} \cdot (\frac{1}{9 \cdot a ^{2} \cdot b ^{3}})^{4}

What is (x-1)(x-2)-(x-3)(x-4)+(x+5)(x+6) ?
The solution to (x-1)(x-2)-(x-3)(x-4)+(x+5)(x+6) is x^2+15x+20