What is factor 1+2x-8x^3-16x^4 ?

The solution to factor 1+2x-8x^3-16x^4 is -(2x+1)(2x-1)(4x^2+2x+1)

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factor 1+2x-8x^3-16x^4

factor

1 + 2 x - 8 x^{3} - 16 x^{4}

- (2 x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

Solution steps

1 + 2 x - 8 x^{3} - 16 x^{4}

Write in the standard form

= - 16 x^{4} - 8 x^{3} + 2 x + 1

Factor out

- 1 : - (16 x^{4} + 8 x^{3} - 2 x - 1)

= - (16 x^{4} + 8 x^{3} - 2 x - 1)

Factor

16 x^{4} + 8 x^{3} - 2 x - 1 : (2 x + 1) (2 x - 1) (2^{2} x^{2} + 2 x + 1)

= - (2 x + 1) (2 x - 1) (2^{2} x^{2} + 2 x + 1)

2^{2} = 4

= - (2 x + 1) (2 x - 1) (4 x^{2} + 2 x + 1)

a^{2} \cdot (b + c) - (b + c)^{3}

(x - y)^{3} + (x - y)^{2} + (x - y)

18 x^{2} + 39 x y - 15 y^{2}

\frac{( 4 a ^{4} - 8 a ^{2} \cdot b ^{2} + 4 b ^{4} )}{( a ^{2} \cdot b - b ^{3} )}

(3 + 8) \cdot x^{6} - 42 - 7

What is factor 1+2x-8x^3-16x^4 ?
The solution to factor 1+2x-8x^3-16x^4 is -(2x+1)(2x-1)(4x^2+2x+1)