What is (2x-1)(2x+1)(4x^2+1)(16x^4+1)+1-256x^8 ?

The solution to (2x-1)(2x+1)(4x^2+1)(16x^4+1)+1-256x^8 is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (2x-1)(2x+1)(4x^2+1)(16x^4+1)+1-256x^8

simplify

(2 x - 1) (2 x + 1) (4 x^{2} + 1) (16 x^{4} + 1) + 1 - 256 x^{8}

0

Solution steps

(2 x - 1) (2 x + 1) (4 x^{2} + 1) (16 x^{4} + 1) + 1 - 256 x^{8}

Expand

(2 x - 1) (2 x + 1) (4 x^{2} + 1) (16 x^{4} + 1) : 256 x^{8} - 1

= 256 x^{8} - 1 + 1 - 256 x^{8}

Group like terms

= 256 x^{8} - 256 x^{8} - 1 + 1

Add similar elements:

256 x^{8} - 256 x^{8} = 0

= - 1 + 1

Add the numbers:

- 1 + 1 = 0

= 0

(a^{2} - 3 a) (a^{2} - 3 a + 7) + 10

(2 - x) (4 - x)

4 a^{2} - 4 b^{2} + 4 a + 1

2 (2^{n} - 1)

x^{3} (3 x + 1)

What is (2x-1)(2x+1)(4x^2+1)(16x^4+1)+1-256x^8 ?
The solution to (2x-1)(2x+1)(4x^2+1)(16x^4+1)+1-256x^8 is 0