What is (3x^{-4}*y^5)/((2x^3y^{-7))^{-2}} ?

The solution to (3x^{-4}*y^5)/((2x^3y^{-7))^{-2}} is (12x^2)/(y^9)

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simplify (3x^{-4}*y^5)/((2x^3y^{-7))^{-2}}

simplify

\frac{3 x ^{- 4} \cdot y ^{5}}{( 2 x ^{3} y ^{- 7} ) ^{- 2}}

\frac{12 x ^{2}}{y ^{9}}

Solution steps

\frac{3 x ^{- 4} y ^{5}}{( 2 x ^{3} y ^{- 7} ) ^{- 2}}

Simplify

3 x^{- 4} y^{5} : \frac{3 y ^{5}}{x ^{4}}

= \frac{\frac{3 y ^{5}}{x ^{4}}}{( 2 x ^{3} y ^{- 7} ) ^{- 2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{3 y ^{5}}{x ^{4} ( 2 x ^{3} y ^{- 7} ) ^{- 2}}

Simplify

x^{4} (2 x^{3} y^{- 7})^{- 2} : \frac{y ^{14}}{4 x ^{2}}

= \frac{3 y ^{5}}{\frac{y ^{14}}{4 x ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{3 y ^{5} \cdot 4 x ^{2}}{y ^{14}}

Cancel

\frac{3 y ^{5} \cdot 4 x ^{2}}{y ^{14}} : \frac{12 x ^{2}}{y ^{9}}

= \frac{12 x ^{2}}{y ^{9}}

(- a + 2 b)^{3}

8 x^{3} + 36 x^{2} + 54 x + 27

(2 x^{2} + 1)^{6}

f (x) = (\frac{x - 1}{2})^{\frac{1}{4}} - 13 + 5 x

\frac{( 1 - x ^{2} )}{( 1 + x ^{2} )}

What is (3x^{-4}*y^5)/((2x^3y^{-7))^{-2}} ?
The solution to (3x^{-4}*y^5)/((2x^3y^{-7))^{-2}} is (12x^2)/(y^9)