What are the solutions to the equation x^2+(4)^2=(13)^2 ?

The solutions to the equation x^2+(4)^2=(13)^2 are x=3sqrt(17),x=-3sqrt(17)

Find the zeros of x^2+(4)^2=(13)^2

The zeros of x^2+(4)^2=(13)^2 are x=3sqrt(17),x=-3sqrt(17)

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x^{2} + (4)^{2} = (13)^{2}

x = 317, x = - 317

Decimal Notation

x = 12.36931 \dots, x = - 12.36931 \dots

Solution steps

x^{2} + (4)^{2} = (13)^{2}

Expand

x^{2} + 4^{2} : x^{2} + 16

Expand

1 3^{2} : 169

x^{2} + 16 = 169

Move

16

to the right side

x^{2} = 153

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 153, x = - 153

153 = 317

- 153 = - 317

x = 317, x = - 317

- x^{2} + 8 x - 15

550 (0.375) = c^{0.75}

3 X - 3 = \frac{1}{2} X - 23

2 (2 x^{2} + 3) = 11 x

(\frac{- 6 a ^{- 9} b ^{5}}{2 a ^{2} b ^{- 4}})^{4}

What are the solutions to the equation x^2+(4)^2=(13)^2 ?
The solutions to the equation x^2+(4)^2=(13)^2 are x=3sqrt(17),x=-3sqrt(17)
Find the zeros of x^2+(4)^2=(13)^2
The zeros of x^2+(4)^2=(13)^2 are x=3sqrt(17),x=-3sqrt(17)