What is l^{-1}*{log_{10}(((s+1))/((s-1)))} ?

The solution to l^{-1}*{log_{10}(((s+1))/((s-1)))} is (log_{10}(s+1)-log_{10}(s-1))/l

Popular >

simplify l^{-1}*{log_{10}(((s+1))/((s-1)))}

simplify

l^{- 1} \cdot {lo g_{10} (\frac{( s + 1 )}{( s - 1 )})}

\frac{lo g _{10} ( s + 1 ) - lo g _{10} ( s - 1 )}{l}

Solution steps

l^{- 1} (lo g_{10} (\frac{s + 1}{s - 1}))

Apply rule:

(a) = a

(lo g_{10} (\frac{s + 1}{s - 1})) = lo g_{10} (\frac{s + 1}{s - 1})

= l^{- 1} lo g_{10} (\frac{s + 1}{s - 1})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{s + 1}{s - 1}) = lo g_{10} (s + 1) - lo g_{10} (s - 1)

= l^{- 1} (lo g_{10} (s + 1) - lo g_{10} (s - 1))

Simplify

l^{- 1} (lo g_{10} (s + 1) - lo g_{10} (s - 1)) : \frac{lo g _{10} ( s + 1 ) - lo g _{10} ( s - 1 )}{l}

= \frac{lo g _{10} ( s + 1 ) - lo g _{10} ( s - 1 )}{l}

\frac{1}{3} \cdot (\frac{1}{( 3 n - 1 )} - \frac{1}{( 3 n + 2 )})

(2 m - 5)^{3}

\frac{( 2 x ) ^{5} ( 2 ^{\frac{1}{2}} x ^{- 3} ) ^{2} ( x ) 1}{5}

(1 - a)^{- 1}

\frac{( x ^{2} )}{( y ^{2} )} - 2 + \frac{( y ^{2} )}{( x ^{2} )}

What is l^{-1}*{log_{10}(((s+1))/((s-1)))} ?
The solution to l^{-1}*{log_{10}(((s+1))/((s-1)))} is (log_{10}(s+1)-log_{10}(s-1))/l