What is factor 14x^3+9x^2-4 ?

The solution to factor 14x^3+9x^2-4 is (2x-1)(7x^2+8x+4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 14x^3+9x^2-4

factor

14 x^{3} + 9 x^{2} - 4

(2 x - 1) (7 x^{2} + 8 x + 4)

Solution steps

14 x^{3} + 9 x^{2} - 4

Use the rational root theorem

= (2 x - 1) \frac{14 x ^{3} + 9 x ^{2} - 4}{2 x - 1}

\frac{14 x ^{3} + 9 x ^{2} - 4}{2 x - 1} = 7 x^{2} + 8 x + 4

= (2 x - 1) (7 x^{2} + 8 x + 4)

\frac{( 18 x + 15 )}{3}

a^{3} - \frac{1}{( a ^{3} )} - 2 a + \frac{2}{a}

\frac{( x ^{2} - 2 x - 3 )}{( x - 3 )}

tan (x) sin (x) + sec (x) cos^{2} (x)

(2 n^{2} - 1)^{2}

What is factor 14x^3+9x^2-4 ?
The solution to factor 14x^3+9x^2-4 is (2x-1)(7x^2+8x+4)