What is x^6-3a^4+sqrt(2x)+5x^2+7x^5+4 ?

The solution to x^6-3a^4+sqrt(2x)+5x^2+7x^5+4 is x^6-3a^4+sqrt(2)sqrt(x)+5x^2+7x^5+4

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simplify x^6-3a^4+sqrt(2x)+5x^2+7x^5+4

simplify

x^{6} - 3 a^{4} + 2 x + 5 x^{2} + 7 x^{5} + 4

x^{6} - 3 a^{4} + 2 x + 5 x^{2} + 7 x^{5} + 4

Solution steps

x^{6} - 3 a^{4} + 2 x + 5 x^{2} + 7 x^{5} + 4

Apply radical rule:

assuming

a \geq 0, b \geq 0

= x^{6} - 3 a^{4} + 2 x + 5 x^{2} + 7 x^{5} + 4

(x + 1)^{20}

\frac{( 8 \frac{a ^{3}}{27} x ^{- 3} ) ^{- 1}}{3}

250 x^{3} - 16 y^{3}

\frac{- 2 b}{a}

(4 x + 8 y)^{3}

What is x^6-3a^4+sqrt(2x)+5x^2+7x^5+4 ?
The solution to x^6-3a^4+sqrt(2x)+5x^2+7x^5+4 is x^6-3a^4+sqrt(2)sqrt(x)+5x^2+7x^5+4