What is 4*(5+2x)^3-2sin(3-2x)+5cos(e)c^2*(3-x)5 ?

The solution to 4*(5+2x)^3-2sin(3-2x)+5cos(e)c^2*(3-x)5 is 4(5+2x)^3-2sin(3-2x)+25cos(e)c^2(3-x)

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simplify 4(5+2x)^3-2sin(3-2x)+5cos(e)c^2(3-x)5

simplify

4 \cdot (5 + 2 x)^{3} - 2 sin (3 - 2 x) + 5 cos (e) c^{2} \cdot (3 - x) 5

4 (5 + 2 x)^{3} - 2 sin (3 - 2 x) + 25 cos (e) c^{2} (3 - x)

Solution steps

4 (5 + 2 x)^{3} - 2 sin (3 - 2 x) + 5 cos (e) c^{2} (3 - x) \cdot 5

Multiply the numbers:

5 \cdot 5 = 25

= 4 (2 x + 5)^{3} - 2 sin (- 2 x + 3) + 25 cos (e) c^{2} (- x + 3)

(\frac{( 2 a ^{3} )}{( b ^{4} )})^{3}

8 x^{6} + 54 x^{2} y^{6} - 27 y 9 - 36 x^{4} y^{3}

sin^{2} (a) + 3 sin (a) cos (a)

324.5 + 54.68 - 23 \cdot 1.4

(4 r - 5 a)^{4}

What is 4*(5+2x)^3-2sin(3-2x)+5cos(e)c^2*(3-x)5 ?
The solution to 4*(5+2x)^3-2sin(3-2x)+5cos(e)c^2*(3-x)5 is 4(5+2x)^3-2sin(3-2x)+25cos(e)c^2(3-x)