What is (a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)+1 ?

The solution to (a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)+1 is a^{16}

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simplify (a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)+1

simplify

(a - 1) (a + 1) (a^{2} + 1) (a^{4} + 1) (a^{8} + 1) + 1

a^{16}

Solution steps

(a - 1) (a + 1) (a^{2} + 1) (a^{4} + 1) (a^{8} + 1) + 1

Expand

(a - 1) (a + 1) (a^{2} + 1) (a^{4} + 1) (a^{8} + 1) : a^{16} - 1

= a^{16} - 1 + 1

Add the numbers:

- 1 + 1 = 0

= a^{16}

12 x - 3 x (x + 9)

(\frac{1}{2 \cdot x - 3})^{3}

81 r^{2} - s^{4}

(\frac{- 2}{3 x + y})^{3}

(6 x + 6 y)^{3}

What is (a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)+1 ?
The solution to (a-1)(a+1)(a^2+1)(a^4+1)(a^8+1)+1 is a^{16}