What is ((7x^6-8x^5*y+x^4*y^3))/((1/2*x^3)) ?

The solution to ((7x^6-8x^5*y+x^4*y^3))/((1/2*x^3)) is 2x(7x^2-8xy+y^3)

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simplify ((7x^6-8x^5y+x^4y^3))/((1/2*x^3))

simplify

\frac{( 7 x ^{6} - 8 x ^{5} \cdot y + x ^{4} \cdot y ^{3} )}{( \frac{1}{2} \cdot x ^{3} )}

2 x (7 x^{2} - 8 x y + y^{3})

Solution steps

\frac{7 x ^{6} - 8 x ^{5} y + x ^{4} y ^{3}}{\frac{1}{2} x ^{3}}

Factor

7 x^{6} - 8 x^{5} y + x^{4} y^{3} : x^{4} (7 x^{2} - 8 x y + y^{3})

= \frac{x ^{4} ( 7 x ^{2} - 8 x y + y ^{3} )}{\frac{1}{2} x ^{3}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{4} = x^{3} x

= \frac{x ^{3} x ( 7 x ^{2} - 8 x y + y ^{3} )}{\frac{1}{2} x ^{3}}

Cancel the common factor:

x^{3}

= \frac{x ( 7 x ^{2} - 8 x y + y ^{3} )}{\frac{1}{2}}

Simplify

\frac{x ( 7 x ^{2} - 8 x y + y ^{3} )}{\frac{1}{2}} : x (7 x^{2} - 8 x y + y^{3}) \cdot 2

= x (7 x^{2} - 8 x y + y^{3}) \cdot 2

= 2 x (7 x^{2} - 8 x y + y^{3})

(3 x - 5 y)^{3} + (3 x - 5 y)^{3}

- 8 y^{2} - 36 y - 35

(n - (n - 2))!

(64 m^{2} \cdot n)^{10}

610 x y + 63 x y^{2} + 135 y

What is ((7x^6-8x^5*y+x^4*y^3))/((1/2*x^3)) ?
The solution to ((7x^6-8x^5*y+x^4*y^3))/((1/2*x^3)) is 2x(7x^2-8xy+y^3)