What is factor 64+a^{12} ?

The solution to factor 64+a^{12} is (a^2+2a+2)(a^2-2a+2)(a^8-4a^4+16)

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factor 64+a^{12}

factor

64 + a^{12}

(a^{2} + 2 a + 2) (a^{2} - 2 a + 2) (a^{8} - 4 a^{4} + 16)

Solution steps

64 + a^{12}

Write in the standard form

= a^{12} + 64

Apply exponent rules

= (a^{4})^{3} + 4^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(a^{4})^{3} + 4^{3} = (a^{4} + 4) (a^{8} - 4 a^{4} + 4^{2})

= (a^{4} + 4) (a^{8} - 4 a^{4} + 4^{2})

Factor

a^{4} + 4 : (a^{2} + 2 a + 2) (a^{2} - 2 a + 2)

= (a^{2} + 2 a + 2) (a^{2} - 2 a + 2) (a^{8} - 4 a^{4} + 4^{2})

4^{2} = 16

= (a^{2} + 2 a + 2) (a^{2} - 2 a + 2) (a^{8} - 4 a^{4} + 16)

k^{5} - 7 k^{3} - 5 k^{2} + 35

(3 x + 1)^{3} + (2 x - 1)^{3} + (2 x + 3)^{2} + 8 x

7 a^{3} + 56 b^{3}

x^{2} + 3 3 x + 6

2167924 - 910 b - 4 c^{2} - a^{46} - 93979 e^{31081} e

What is factor 64+a^{12} ?
The solution to factor 64+a^{12} is (a^2+2a+2)(a^2-2a+2)(a^8-4a^4+16)