What is factor-a^4+4b^2 ?

The solution to factor-a^4+4b^2 is (2b+a^2)(2b-a^2)

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factor-a^4+4b^2

factor

- a^{4} + 4 b^{2}

(2 b + a^{2}) (2 b - a^{2})

Solution steps

- a^{4} + 4 b^{2}

= 4 b^{2} - a^{4}

4 b^{2} = (2 b)^{2}

a^{4} = (a^{2})^{2}

= (2 b)^{2} - (a^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 b)^{2} - (a^{2})^{2} = (2 b + a^{2}) (2 b - a^{2})

= (2 b + a^{2}) (2 b - a^{2})

- 2 x (x + 3) - (x + 1) (x - 2)

(x^{- 1} \cdot y^{3})^{\frac{1}{2}}

\frac{2 ^{3} ( x ^{2} ) ^{3}}{2 ^{2}}

(x - y + 2 z)^{3}

(3 x^{2} + 4 x y + 5 y^{2}) (7 x^{2} + 9 y^{2})