What is ((3y^2+8y+4))/((y^2-4)) ?

The solution to ((3y^2+8y+4))/((y^2-4)) is (3y+2)/(y-2)

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simplify ((3y^2+8y+4))/((y^2-4))

simplify

\frac{( 3 y ^{2} + 8 y + 4 )}{( y ^{2} - 4 )}

\frac{3 y + 2}{y - 2}

Solution steps

\frac{3 y ^{2} + 8 y + 4}{y ^{2} - 4}

Factor

3 y^{2} + 8 y + 4 : (3 y + 2) (y + 2)

= \frac{( 3 y + 2 ) ( y + 2 )}{y ^{2} - 4}

Factor

y^{2} - 4 : (y + 2) (y - 2)

= \frac{( 3 y + 2 ) ( y + 2 )}{( y + 2 ) ( y - 2 )}

Cancel the common factor:

y + 2

= \frac{3 y + 2}{y - 2}

(- 2^{- 1} x^{- n})^{- 3}

\frac{54}{24 - 3 x [ \frac{( 4 \cdot 5 - 2 \cdot 5 )}{2} + 1 ]}

64 x^{3} - 729 y^{3}

a (a - 1) y^{2} - y - a (a + 1)

\frac{d ^{923109} i 416934622}{- 4 + 1158125}

What is ((3y^2+8y+4))/((y^2-4)) ?
The solution to ((3y^2+8y+4))/((y^2-4)) is (3y+2)/(y-2)