What are the solutions to the equation r^2-2r+2=0 ?

The solutions to the equation r^2-2r+2=0 are r=1+i,r=1-i

Find the zeros of r^2-2r+2=0

The zeros of r^2-2r+2=0 are r=1+i,r=1-i

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r^{2} - 2 r + 2 = 0

r = 1 + i, r = 1 - i

Solution steps

r^{2} - 2 r + 2 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

r_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, r_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

r = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

r = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

r = 1 + i, r = 1 - i

(3 u - 5) (8 + u) = 0

4 x^{4} - 13 x^{2} + 9

\frac{d}{18} + 6 = 16

(4 + 5)^{2}

x^{8} - 4 x^{4} + 4

What are the solutions to the equation r^2-2r+2=0 ?
The solutions to the equation r^2-2r+2=0 are r=1+i,r=1-i
Find the zeros of r^2-2r+2=0
The zeros of r^2-2r+2=0 are r=1+i,r=1-i