What is factor x^4+5x^3-5x^2+5x-6 ?

The solution to factor x^4+5x^3-5x^2+5x-6 is (x-1)(x+6)(x^2+1)

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factor x^4+5x^3-5x^2+5x-6

factor

x^{4} + 5 x^{3} - 5 x^{2} + 5 x - 6

(x - 1) (x + 6) (x^{2} + 1)

Solution steps

x^{4} + 5 x^{3} - 5 x^{2} + 5 x - 6

Use the rational root theorem

= (x - 1) \frac{x ^{4} + 5 x ^{3} - 5 x ^{2} + 5 x - 6}{x - 1}

\frac{x ^{4} + 5 x ^{3} - 5 x ^{2} + 5 x - 6}{x - 1} = x^{3} + 6 x^{2} + x + 6

= (x - 1) (x^{3} + 6 x^{2} + x + 6)

Factor

x^{3} + 6 x^{2} + x + 6 : (x + 6) (x^{2} + 1)

= (x - 1) (x + 6) (x^{2} + 1)

16 x^{4} - 25 y^{6}

tan^{2} (a) - sin^{2} (a) tan^{2} (a)

(x^{7})^{11}

(1 - 3 x)^{5}

(\frac{2 x - 1}{3 x})^{2}

What is factor x^4+5x^3-5x^2+5x-6 ?
The solution to factor x^4+5x^3-5x^2+5x-6 is (x-1)(x+6)(x^2+1)