What are the solutions to the equation x^2+6x-72=0 ?

The solutions to the equation x^2+6x-72=0 are x=6,x=-12

Find the zeros of x^2+6x-72=0

The zeros of x^2+6x-72=0 are x=6,x=-12

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x^{2} + 6 x - 72 = 0

x = 6, x = - 12

Solution steps

x^{2} + 6 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 72) = 18

x_{1, 2} = \frac{- 6 \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 18}{2 \cdot 1}, x_{2} = \frac{- 6 - 18}{2 \cdot 1}

x = \frac{- 6 + 18}{2 \cdot 1} : 6

x = \frac{- 6 - 18}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

x = 6, x = - 12

\frac{21 - ( - 10 )}{1 0 ^{- x}} \leq 1023

lo g_{6} (5) + 2 lo g_{6} (x^{2} + 1)

- 1 - \frac{4}{3}

\frac{10}{2 π}

(\frac{5}{3})^{- 1}

What are the solutions to the equation x^2+6x-72=0 ?
The solutions to the equation x^2+6x-72=0 are x=6,x=-12
Find the zeros of x^2+6x-72=0
The zeros of x^2+6x-72=0 are x=6,x=-12