What is (4a^{-3}b^{-3})^{-2} ?

The solution to (4a^{-3}b^{-3})^{-2} is (a^6b^6)/(16)

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simplify (4a^{-3}b^{-3})^{-2}

simplify

(4 a^{- 3} b^{- 3})^{- 2}

\frac{a ^{6} b ^{6}}{16}

Solution steps

(4 a^{- 3} b^{- 3})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(4 a^{- 3} b^{- 3})^{- 2} = \frac{1}{( 4 a ^{- 3} b ^{- 3} ) ^{2}}

= \frac{1}{( 4 a ^{- 3} b ^{- 3} ) ^{2}}

Simplify

(4 a^{- 3} b^{- 3})^{2} : \frac{16}{a ^{6} b ^{6}}

= \frac{1}{\frac{16}{a ^{6} b ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a ^{6} b ^{6}}{16}

(x^{2 a - 1} + y^{b}) (x^{a} + y^{b})

\frac{6}{( 5 x y )} + \frac{6}{( 11 x y ^{2} )}

cos^{22} (x) - sin^{22} (x)

\frac{( 5 x ^{4} - 3 x ^{3} + 2 x ^{2} - 7 x + 3 )}{( x - 1 )}

arctan (\frac{( 2 a ^{x} )}{( 1 - a ^{2 x} )})

What is (4a^{-3}b^{-3})^{-2} ?
The solution to (4a^{-3}b^{-3})^{-2} is (a^6b^6)/(16)