What is ((4/((x^2-7x+12)))+3)/((3-x)) ?

The solution to ((4/((x^2-7x+12)))+3)/((3-x)) is (3x^2-21x+40)/((x^2-7x+12)(3-x))

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simplify ((4/((x^2-7x+12)))+3)/((3-x))

simplify

\frac{( \frac{4}{( x ^{2} - 7 x + 12 )} ) + 3}{( 3 - x )}

\frac{3 x ^{2} - 21 x + 40}{( x ^{2} - 7 x + 12 ) ( 3 - x )}

Solution steps

\frac{( \frac{4}{x ^{2} - 7 x + 12} ) + 3}{3 - x}

Apply rule:

(a) = a

(\frac{4}{x ^{2} - 7 x + 12}) = \frac{4}{x ^{2} - 7 x + 12}

= \frac{\frac{4}{x ^{2} - 7 x + 12} + 3}{3 - x}

Join

\frac{4}{x ^{2} - 7 x + 12} + 3 : \frac{3 x ^{2} - 21 x + 40}{x ^{2} - 7 x + 12}

= \frac{\frac{3 x ^{2} - 21 x + 40}{x ^{2} - 7 x + 12}}{3 - x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{3 x ^{2} - 21 x + 40}{( x ^{2} - 7 x + 12 ) ( 3 - x )}

79 x^{12} + 12 - 60 x^{12}

4 x^{2} - 9 y^{2} - 4 x - 6 y

2 (x^{2})^{2} - 4 x - 1

(4 x - y)^{3} + (4 x + y)^{2}

7 m^{2} \cdot n^{3} + 14 m^{3} \cdot n^{2} - 21 m^{3} \cdot n^{4}

What is ((4/((x^2-7x+12)))+3)/((3-x)) ?
The solution to ((4/((x^2-7x+12)))+3)/((3-x)) is (3x^2-21x+40)/((x^2-7x+12)(3-x))