What is ((6+2))/((sqrt(b^2-4))) ?

The solution to ((6+2))/((sqrt(b^2-4))) is 8/(sqrt(b^2-4))

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simplify ((6+2))/((sqrt(b^2-4)))

simplify

\frac{( 6 + 2 )}{( b ^{2} - 4 )}

\frac{8}{b ^{2} - 4}

Solution steps

\frac{6 + 2}{b ^{2} - 4}

Add the numbers:

6 + 2 = 8

= \frac{8}{b ^{2} - 4}

(3 x + 2 y - 4 z)^{2}

\frac{( 18 a - 10 b + 6 c )}{2}

- 5 x + 5 y

18 x - 42 y + 30 z

x^{3} \cdot y + x \cdot y^{3}

What is ((6+2))/((sqrt(b^2-4))) ?
The solution to ((6+2))/((sqrt(b^2-4))) is 8/(sqrt(b^2-4))