What is factor 4cos^2(16x)-1 ?

The solution to factor 4cos^2(16x)-1 is (2cos(16x)+1)(2cos(16x)-1)

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factor 4cos^2(16x)-1

factor

4 cos^{2} (16 x) - 1

(2 cos (16 x) + 1) (2 cos (16 x) - 1)

Solution steps

4 cos^{2} (16 x) - 1

4 cos^{2} (16 x) = (2 cos (16 x))^{2}

1 = 1^{2}

= (2 cos (16 x))^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 cos (16 x))^{2} - 1^{2} = (2 cos (16 x) + 1) (2 cos (16 x) - 1)

= (2 cos (16 x) + 1) (2 cos (16 x) - 1)

- 4 (3 n - 1)

14 x + 21 y + 7 z

(3 x 1 0^{- 3})^{4}

x^{16} + x^{10} + x^{7} + x

a^{7} \cdot a^{5}

What is factor 4cos^2(16x)-1 ?
The solution to factor 4cos^2(16x)-1 is (2cos(16x)+1)(2cos(16x)-1)