What are the solutions to the equation 3x^2-2x-40=0 ?

The solutions to the equation 3x^2-2x-40=0 are x=4,x=-10/3

Find the zeros of 3x^2-2x-40=0

The zeros of 3x^2-2x-40=0 are x=4,x=-10/3

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3 x^{2} - 2 x - 40 = 0

x = 4, x = - \frac{10}{3}

Decimal Notation

x = 4, x = - 3.33333 \dots

Solution steps

3 x^{2} - 2 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 3 ( - 40 )}{2 \cdot 3}

(- 2)^{2} - 4 \cdot 3 (- 40) = 22

x_{1, 2} = \frac{- ( - 2 ) \pm 22}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 22}{2 \cdot 3}, x_{2} = \frac{- ( - 2 ) - 22}{2 \cdot 3}

x = \frac{- ( - 2 ) + 22}{2 \cdot 3} : 4

x = \frac{- ( - 2 ) - 22}{2 \cdot 3} : - \frac{10}{3}

The solutions to the quadratic equation are:

x = 4, x = - \frac{10}{3}

(x + 3) (x - 3) = 7

9 (x - 2) = 18

12 x + 4 = 20 x - 12

- \frac{19}{2} (\frac{1}{100}) + \frac{19}{2}

n - 2 = \frac{n ( n - 3 )}{2}

What are the solutions to the equation 3x^2-2x-40=0 ?
The solutions to the equation 3x^2-2x-40=0 are x=4,x=-10/3
Find the zeros of 3x^2-2x-40=0
The zeros of 3x^2-2x-40=0 are x=4,x=-10/3