What is simplify-x^2+1/((x^2))+2-2x-2/x ?

The solution to simplify-x^2+1/((x^2))+2-2x-2/x is (-x^4+1-2x+2x^2-2x^3)/(x^2)

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simplify-x^2+1/((x^2))+2-2x-2/x

simplify

- x^{2} + \frac{1}{( x ^{2} )} + 2 - 2 x - \frac{2}{x}

\frac{- x ^{4} + 1 - 2 x + 2 x ^{2} - 2 x ^{3}}{x ^{2}}

Solution steps

- x^{2} + \frac{1}{x ^{2}} + 2 - 2 x - \frac{2}{x}

Join

\frac{1}{x ^{2}} - \frac{2}{x} : \frac{1 - 2 x}{x ^{2}}

= - x^{2} + \frac{1 - 2 x}{x ^{2}} + 2 - 2 x

Convert

- x^{2}

to fraction

: \frac{- x ^{4}}{x ^{2}}

Convert

2

to fraction

: \frac{2 x ^{2}}{x ^{2}}

Convert

2 x

to fraction

: \frac{2 x ^{3}}{x ^{2}}

= \frac{- x ^{4}}{x ^{2}} + \frac{1 - 2 x}{x ^{2}} + \frac{2 x ^{2}}{x ^{2}} - \frac{2 x ^{3}}{x ^{2}}

Apply the fraction rule:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- x ^{4} + 1 - 2 x + 2 x ^{2} - 2 x ^{3}}{x ^{2}}

12 x^{2} \cdot y + 6 x \cdot y^{3}

5 y x^{2} y

(2 x^{- 2} \cdot y^{3})^{3}

- 8 x y - 7 x y

(- 4 x^{6} y) (2 x^{- 2} y^{5})^{3}

What is simplify-x^2+1/((x^2))+2-2x-2/x ?
The solution to simplify-x^2+1/((x^2))+2-2x-2/x is (-x^4+1-2x+2x^2-2x^3)/(x^2)