What is ((x^2-3x))/((x^2-9)) ?

The solution to ((x^2-3x))/((x^2-9)) is x/(x+3)

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simplify ((x^2-3x))/((x^2-9))

simplify

\frac{( x ^{2} - 3 x )}{( x ^{2} - 9 )}

\frac{x}{x + 3}

Solution steps

\frac{x ^{2} - 3 x}{x ^{2} - 9}

Factor

x^{2} - 3 x : x (x - 3)

= \frac{x ( x - 3 )}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{x ( x - 3 )}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x}{x + 3}

(x + 2) (x + 3)^{3}

(v) 6^{l o g_{6} (5)} + 3^{l o g_{9} (16)}

42.958 x 1 0^{- 3} - 1.87 x 1 0^{- 1}

(x^{2} - 3 x + 1)^{3}

2 \cdot x^{2} + 4 x + 6 - 2 x