What is (1/(3x^2y^{-3)})^{-2} ?

The solution to (1/(3x^2y^{-3)})^{-2} is (9x^4)/(y^6)

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simplify (1/(3x^2y^{-3)})^{-2}

simplify

(\frac{1}{3 x ^{2} y ^{- 3}})^{- 2}

\frac{9 x ^{4}}{y ^{6}}

Solution steps

(\frac{1}{3 x ^{2} y ^{- 3}})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{1}{3 x ^{2} y ^{- 3}})^{- 2} = \frac{1}{( \frac{1}{3 x ^{2} y ^{- 3}} ) ^{2}}

= \frac{1}{( \frac{1}{3 x ^{2} y ^{- 3}} ) ^{2}}

Simplify

(\frac{1}{3 x ^{2} y ^{- 3}})^{2} : \frac{y ^{6}}{9 x ^{4}}

= \frac{1}{\frac{y ^{6}}{9 x ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{9 x ^{4}}{y ^{6}}

4 x^{10} - 2

4033826 - 20201224 - o^{1}

\frac{6 \cdot e ^{- 3} x}{3}

\frac{9 ^{x}}{3 ^{x}}

(x^{10} - 5 y^{2}) 2

What is (1/(3x^2y^{-3)})^{-2} ?
The solution to (1/(3x^2y^{-3)})^{-2} is (9x^4)/(y^6)