What is ((4x^2-49))/((2x+7))-((x^2-16x+64))/((8-x))+((9x^2-6x+1))/((1-3x)) ?

The solution to ((4x^2-49))/((2x+7))-((x^2-16x+64))/((8-x))+((9x^2-6x+1))/((1-3x)) is -14

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simplify ((4x^2-49))/((2x+7))-((x^2-16x+64))/((8-x))+((9x^2-6x+1))/((1-3x))

simplify

\frac{( 4 x ^{2} - 49 )}{( 2 x + 7 )} - \frac{( x ^{2} - 16 x + 64 )}{( 8 - x )} + \frac{( 9 x ^{2} - 6 x + 1 )}{( 1 - 3 x )}

- 14

Solution steps

\frac{4 x ^{2} - 49}{2 x + 7} - \frac{x ^{2} - 16 x + 64}{8 - x} + \frac{9 x ^{2} - 6 x + 1}{1 - 3 x}

\frac{4 x ^{2} - 49}{2 x + 7} = 2 x - 7

\frac{x ^{2} - 16 x + 64}{8 - x} = - x + 8

\frac{9 x ^{2} - 6 x + 1}{1 - 3 x} = - 3 x + 1

= 2 x - 7 - (- x + 8) - 3 x + 1

Group like terms

= - (- x + 8) + 2 x - 3 x - 7 + 1

Add similar elements:

2 x - 3 x = - x

= - (- x + 8) - x - 7 + 1

Add the numbers:

- 7 + 1 = - 6

= - (- x + 8) - x - 6

Apply the distributive law:

- (- a + b) = a - b

- (- x + 8) = x - 8

= x - 8 - x - 6

Group like terms

= x - x - 8 - 6

Add similar elements:

x - x = 0

= - 8 - 6

Subtract the numbers:

- 8 - 6 = - 14

= - 14

3 x^{2} y^{3} - 6 x^{3} y^{4} + 12 x y

x^{4} + 8 x y^{3}

(\frac{a ^{2}}{4})^{2}

\frac{\frac{1}{x ^{2}}}{( 1 + \frac{1}{x ^{2}} ) ^{\frac{3}{2}}}

\frac{x ^{n}}{1 - x ^{2}}

What is ((4x^2-49))/((2x+7))-((x^2-16x+64))/((8-x))+((9x^2-6x+1))/((1-3x)) ?
The solution to ((4x^2-49))/((2x+7))-((x^2-16x+64))/((8-x))+((9x^2-6x+1))/((1-3x)) is -14