What is ((5x^3-2x^2+3x))/((x^3-2x^2)) ?

The solution to ((5x^3-2x^2+3x))/((x^3-2x^2)) is (5x^2-2x+3)/(x(x-2))

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simplify ((5x^3-2x^2+3x))/((x^3-2x^2))

simplify

\frac{( 5 x ^{3} - 2 x ^{2} + 3 x )}{( x ^{3} - 2 x ^{2} )}

\frac{5 x ^{2} - 2 x + 3}{x ( x - 2 )}

Solution steps

\frac{5 x ^{3} - 2 x ^{2} + 3 x}{x ^{3} - 2 x ^{2}}

Factor

5 x^{3} - 2 x^{2} + 3 x : x (5 x^{2} - 2 x + 3)

= \frac{x ( 5 x ^{2} - 2 x + 3 )}{x ^{3} - 2 x ^{2}}

Factor

x^{3} - 2 x^{2} : x^{2} (x - 2)

= \frac{x ( 5 x ^{2} - 2 x + 3 )}{x ^{2} ( x - 2 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{x ( 5 x ^{2} - 2 x + 3 )}{xx ( x - 2 )}

Cancel the common factor:

x

= \frac{5 x ^{2} - 2 x + 3}{x ( x - 2 )}

(\frac{3 a + 1}{4 b})^{3}

x^{2} y^{4} - 4

(n^{3})^{7}!

x - (\frac{( x + 1 )}{2})

(x^{22})^{x}

What is ((5x^3-2x^2+3x))/((x^3-2x^2)) ?
The solution to ((5x^3-2x^2+3x))/((x^3-2x^2)) is (5x^2-2x+3)/(x(x-2))