What is ((16x^4))/((32x^4+48x^4)) ?

The solution to ((16x^4))/((32x^4+48x^4)) is 1/5

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simplify ((16x^4))/((32x^4+48x^4))

simplify

\frac{( 16 x ^{4} )}{( 32 x ^{4} + 48 x ^{4} )}

\frac{1}{5}

Decimal Notation

0.2

Solution steps

\frac{16 x ^{4}}{32 x ^{4} + 48 x ^{4}}

Add similar elements:

32 x^{4} + 48 x^{4} = 80 x^{4}

= \frac{16 x ^{4}}{80 x ^{4}}

Cancel the common factor:

x^{4}

= \frac{16}{80}

Cancel the numbers:

\frac{16}{80} = \frac{1}{5}

= \frac{1}{5}

1 + 128 x^{14}

(5 x + 2 y) + (3 x - 5 y) - (6 x + 4 y)

(\frac{( 3 a ^{2} )}{( a ^{- 2} \cdot b ^{3} \cdot c ^{2} )})^{- 2}

a \cdot a^{\frac{1}{3}}

(x - 5) (250000 x + 9)

What is ((16x^4))/((32x^4+48x^4)) ?
The solution to ((16x^4))/((32x^4+48x^4)) is 1/5